Pascals Principle Lesson 3 Pascals Principle A car

Pascals Principle Lesson 3 Pascals Principle A car

Pascals Principle Lesson 3 Pascals Principle A car hoist in an automotive repair is a hydraulic system. A hydraulic system takes advantage of the property of liquids; they cannot be (easily)

compressed. The relationship between pressure and enclosed fluids was formulated by the French scientist Blaise Pascal. Pascals Principle Pressure applied to an enclosed liquid is transmitted to every part of the liquid and to the walls of the container.

Pascal used this principle in the design of a device called the hydraulic press. A device in which a small force on a small piston is transmitted through an enclosed liquid and applies a large force on a large

piston. A small downward force applied to the small movable piston can produce a large upward force applied to the large moveable piston. According to Pascals

principle, the pressure (pS) on the small piston equals the pressure (PL) on the large piston, or p =p . Thus, since than

, where S or 1 means small and L or 2 means large. The formula can be rearranged to find any unknown. . Just like with the use of pulleys

and levers, there is Actual Mechanical Advantage (AMA) with the ratio , and Ideal Mechanical Advantage (IMA) where . The use of the hydraulic press is widespread, from medical syringes to a cars breaking

system. In each of these cases, a small moveable piston must move a greater distance than the large piston in order to move the same volume of liquid in each cylinder. Example 1 A car of mass 1.4 x 103 kg is hoisted on the

large cylinder of a hydraulic press. The area of the large piston is 0.22 m2, and the area of the small piston is 0.013 m2. A. Calculate the magnitude of the force of the small piston needed to raise the car (at a constant, slow speed) on the larger piston. B. Calculate the pressure, in Pascals and kilpascals, in this hydraulic system. FL = mg

FL = (1.4 x 103 kg) (9.8 m/s2) FL = 1.37 x 104 N AL = 0.22 m2 AS = 0.013 m2 FS = ? FS = 8.1 x 102 N Therefore, the force on the small piston is 8.1 x 102 N

Calculate the pressure, in Pascals and kilopascals, in this hydraulic system. FS = 8.1 x 102 N AS = 0.013 m2 PS = ? PS = 6.2 x 104 pa or 62 kPa Therefore, the pressure in the

hydraulic press is 62 kPa. Car Brakes When you depress a brake pedal, the car transmits the force from your foot to its brakes through a fluid. Since the actual brakes require a much greater force than you could apply with

your leg, your car must also multiply the force of your foot. It does this in two ways: Mechanical advantage(leverage) Pascals Principle The brakes transmit the force to the tires using friction, and the tires transmit that force to the road using friction.

The diagram right, shows the distance from the pedal to the pivot is four times the distance from the cylinder to the pivot, so the force at the pedal will be increased by a factor of four before it is transmitted to the

cylinder. (2nd class lever) The diameter of the brake cylinder is three times the diameter of the pedal cylinder. This further multiplies the force by nine. All together, this system

increases the force of your foot by a factor of 36 (4 x 9 = 36). If you put 10 kg of force on the pedal, 3600 kg will be generated at the wheel squeezing the brake pads

Questions Explain Pascals principle C (1) Explain why Pascals principle does not apply to gas. C (1) Explain how Pascals principle is useful for car brake designers. C (1) Copy the table shown below and calculate all unknowns. T (4)

Copy the table shown below and calculate all unknowns. T (4) FS (N) AS (m2) FL (N) AL (m2)

? 0.25 1.8 x 103 1.5 65

? 5.2 x 102 0.64 5.4 x 102 0.15

?` 1.2 1.4 x 102 2.0 x 10- 7.7 x 103 2 ? In a mining operation, a hydraulic jack can

exert a maximum force of magnitude 2.2 x 103 N on the small piston. The surface area of the small piston is 0.10 m2, and the surface area of the large piston is 2.0 m2. Calculate. The magnitude of the maximum force that can be used to lift a load. T (1) C (1) The mass of that load. T (1) C (1)

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